Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 6 (Q.No. 45)
45.
The normal duration and normal cost of an activity are 10 days and Rs 350/- respectively. The cost slope is Rs 75/- per day. If the crash duration is 8 days, then what is the crash cost of the activity ?
Discussion:
4 comments Page 1 of 1.
Mesbah Ullah said:
4 years ago
Cost slope = Crash cost " Normal cost/Normal time " Crash time.
Omkar sabade said:
4 years ago
Cost slope = (crash cost-normal cost/normal cost-crshcost).
75 = crash cost-350/10 - 8,
Crash cost = 150 + 350,
= 500.
75 = crash cost-350/10 - 8,
Crash cost = 150 + 350,
= 500.
Dibakar said:
4 years ago
Cost slope= (crash cost-normal cost)/(normal time-crash time).
Sadashiva said:
8 years ago
Cost slope= (crash cost-normal cost/normal cost-crshcost).
75=crash cost-350/10-8,
Crash cost=150+350,
= 500.
75=crash cost-350/10-8,
Crash cost=150+350,
= 500.
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