Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 15 (Q.No. 35)
35.
A 12 kg mass rests on a surface for which the coefficient of friction is μ= 0.15. What is the smallest force that can give the mass acceleration of 3 m/s2 ? (Take g = 10 m/s2).
Discussion:
3 comments Page 1 of 1.
Paul said:
4 years ago
umg 12 * .15 * 10 = 18(f1)
f2 = ma =12 * 3 = 36,
f1 + f2 = 54.
f2 = ma =12 * 3 = 36,
f1 + f2 = 54.
(1)
Basavaraj said:
7 years ago
F=0.15 * 3 * 12 = 5.4.
5.4*10=54.
Ans will be option D.
5.4*10=54.
Ans will be option D.
(1)
Pops said:
8 years ago
Please, anyone explain this.
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