Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 8 (Q.No. 19)
19.
A point in an element is stressed as shown in the given figure. What is the value of normal stress on the oblique plane BE ?
Discussion:
5 comments Page 1 of 1.
Vai said:
8 years ago
If fx = fy = normal stress = 100 MPa, txy = shear stress = 0.
Normal stress inclined at an angle 'a' with vertical, fa = (fx + fy)/2 + [(fx - fy)/2]*cos 2a - txy*sin 2a.
fa = (100+100)/2 + 0 + 0 = 100 MPa.
Ans is D.
Normal stress inclined at an angle 'a' with vertical, fa = (fx + fy)/2 + [(fx - fy)/2]*cos 2a - txy*sin 2a.
fa = (100+100)/2 + 0 + 0 = 100 MPa.
Ans is D.
Vivek said:
6 years ago
Stress= 100 Cos2a+ 100 Sin2 a+2*0 cos a * Sin a.
= 100*(1.732/2)Square + 100* (1/2)Square +0.
= 100*3/4 +100 * 1/4,
= 100 N/mm2.
= 100*(1.732/2)Square + 100* (1/2)Square +0.
= 100*3/4 +100 * 1/4,
= 100 N/mm2.
Apcivilian said:
3 years ago
Yes, D is absolutely right. I too agree.
Rocky bhai said:
4 years ago
The right Answer is D.
Kartik said:
8 years ago
sin30 = 100/BE.
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