Civil Engineering - UPSC Civil Service Exam Questions - Discussion

Discussion Forum : UPSC Civil Service Exam Questions - Section 10 (Q.No. 26)
26.
For a symmetrical continuous beam as shown in the figure given above, which one of the following is correct in respect of distribution factors at B ?
δBA : δBC = 3:4
δBA : δBC = 1:2
δBA : δBC = 3:2
δBA : δBC = 3:8
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Rahul verma said:   3 years ago
stiffness for end A.

=3EI/L.

for end C.

=4EI/L.

So,
Distribution factor df=stifness/sum of stiffness.
3/2+4a and 4/7.
The ratio would be 3:4.
(1)

Kotesh said:   6 years ago
Please explain the answer.

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