Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 9)
9.
For total reaction time of 2.5 seconds, coefficient of friction 0.35, design speed 80 km/h, what is the stopping sight distance on a highway ?
Discussion:
13 comments Page 2 of 2.
Virender singh said:
7 years ago
The formula is e * f +v^2/2gf.
Wagh Akash Kailas said:
6 years ago
Formula : v*t+ v*v/2gf.
Convert all in m & s as per value.
Convert all in m & s as per value.
(1)
Shahid hamid said:
3 years ago
SD= vt+(v^2÷2gf).
V=80, v=80÷3.6=22.22{assume 3.6 by IRC),
SD=22.22+{(22.22)*(22.22)}÷2*9.8*0.35,
SD=127.52.
V=80, v=80÷3.6=22.22{assume 3.6 by IRC),
SD=22.22+{(22.22)*(22.22)}÷2*9.8*0.35,
SD=127.52.
(1)
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