# Civil Engineering - UPSC Civil Service Exam Questions - Discussion

Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 9)

9.

For total reaction time of 2.5 seconds, coefficient of friction 0.35, design speed 80 km/h, what is the stopping sight distance on a highway ?

Discussion:

13 comments Page 1 of 2.
Shahid hamid said:
2 years ago

SD= vt+(v^2Ã·2gf).

V=80, v=80Ã·3.6=22.22{assume 3.6 by IRC),

SD=22.22+{(22.22)*(22.22)}Ã·2*9.8*0.35,

SD=127.52.

V=80, v=80Ã·3.6=22.22{assume 3.6 by IRC),

SD=22.22+{(22.22)*(22.22)}Ã·2*9.8*0.35,

SD=127.52.

(1)

Wagh Akash Kailas said:
5 years ago

Formula : v*t+ v*v/2gf.

Convert all in m & s as per value.

Convert all in m & s as per value.

(1)

Virender singh said:
6 years ago

The formula is e * f +v^2/2gf.

Dolly said:
7 years ago

Here, Stopping distance =d1+d2.

d1=0.7*v ,d2=v^2/(254f),

v=80 f=0.35.

d1=0.7*v ,d2=v^2/(254f),

v=80 f=0.35.

(1)

Bhosale Vrushali Ramesh said:
8 years ago

If speed is in Kmph then formula for SSD is;

SSD = (0.278 * v * t ) + (v^2/254f).

SSD = (0.278 * 80 * 205) + ((80^2) / (254 * 0.35)) = 127.59.

SSD = (0.278 * v * t ) + (v^2/254f).

SSD = (0.278 * 80 * 205) + ((80^2) / (254 * 0.35)) = 127.59.

(2)

Mani Bhushan said:
8 years ago

V * t + v^2/(2gf).

V = 80/3.6 = 22.2.

T = 2.5 sec.

G = 9.8.

F = 3.5.

SSD = 127m.

V = 80/3.6 = 22.2.

T = 2.5 sec.

G = 9.8.

F = 3.5.

SSD = 127m.

(1)

Abhay said:
9 years ago

SSD = LAG DISTANCE + BRAKING DISTANCE.

Design speed = 80 Km/hr => v = 80x1000/(60x60) m/sec = 22.22 m/sec.

Reaction time = 2.5 sec.

Coefficient of friction f = 0.35.

= vt + v^2/(2gf).

= 22.22*2.5 + 22.22^2/(2*9.81*0.35).

SSD = 127.45 m.

Design speed = 80 Km/hr => v = 80x1000/(60x60) m/sec = 22.22 m/sec.

Reaction time = 2.5 sec.

Coefficient of friction f = 0.35.

= vt + v^2/(2gf).

= 22.22*2.5 + 22.22^2/(2*9.81*0.35).

SSD = 127.45 m.

Dipak said:
9 years ago

Without calculator can't be calculated.

Adel abu ghazaleh said:
9 years ago

SSD = Recognizing distance + Breaking distance.

= V(in m/s)*t(in sec)+V^2(in m/s)/(2g (f-G)).

Where G is the difference in slope.

= 80*1000/3600*2.5+(80*1000/3600)^2/(2*9.81*0.35).

= 127.468 roughly 127.

= V(in m/s)*t(in sec)+V^2(in m/s)/(2g (f-G)).

Where G is the difference in slope.

= 80*1000/3600*2.5+(80*1000/3600)^2/(2*9.81*0.35).

= 127.468 roughly 127.

Akhilesh said:
9 years ago

SSD = Lag Distance+Braking Distance.

= V*t+V^2/2gf.

= 22.22*2.5+{22.22/2*9.81*0.35}.

= 127.

= V*t+V^2/2gf.

= 22.22*2.5+{22.22/2*9.81*0.35}.

= 127.

Post your comments here:

Your comments will be displayed after verification.

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers

© IndiaBIX™ Technologies