Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 22 (Q.No. 4)
4.
For the beam shown in figure, what are the distribution factors at joint B ?
Discussion:
1 comments Page 1 of 1.
Rahul said:
2 years ago
K1 = 4EI/L1 = .5EI
K2 = 3EI/L2 = .5EI
Sum of K1 + K2.
.5+.5=1.
Now, the factors are;
.5/1 & .5/1
ie 0.5&0.5.
K2 = 3EI/L2 = .5EI
Sum of K1 + K2.
.5+.5=1.
Now, the factors are;
.5/1 & .5/1
ie 0.5&0.5.
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