Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 23 (Q.No. 21)
21.
Due to horizontal pull of 60 kN at C, what is the force induced in the member AB?
Discussion:
2 comments Page 1 of 1.
Abdelhamid.H said:
8 years ago
Get reaction o point A = 80 kn down , sum vertical force = 0 => 80-F*4/5 = 0 . F =100 KN tension.
Rahul said:
2 years ago
Ra = 80.
F(AB) * sinx = 80.
F(AB) = 80 * 5/4.
= 100.
F(AB) * sinx = 80.
F(AB) = 80 * 5/4.
= 100.
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