Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 22 (Q.No. 17)
17.
A catchment has an area of 150 hectares and a run-off/rainfall ratio of 0.40. If due to 10 cm rainfall over the catchment, a stream flow at the catchment outlet lasts for 10 hours, what is the average stream flow in the period ?
Discussion:
2 comments Page 1 of 1.
Rahul said:
3 years ago
Runoff = 150 × 10^4 × 0.4 × 0.1 = 60,000.
Average stream flow = 60,000/10 × 60 = 100.
Average stream flow = 60,000/10 × 60 = 100.
Karthik said:
7 years ago
Solution:
Runoff = 150*104*0.4*0.1 = 60,000 m3,
Average streamflow.
= 60,00010 * 60 = 100m3/minute.
Runoff = 150*104*0.4*0.1 = 60,000 m3,
Average streamflow.
= 60,00010 * 60 = 100m3/minute.
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