Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 11 (Q.No. 39)
39.
A municipal sewage has BOD5 of 200 mg/l. It is proposed to treat it and dispose off into a marine environment. For what minimum efficiency should the sewage treatment plant be designed ?
Discussion:
3 comments Page 1 of 1.
Basavaraj said:
7 years ago
B is the correct Answer.
Hameid said:
6 years ago
C is the Answer.
(200-100) 200 * 100 = 50%.
(200-100) 200 * 100 = 50%.
Rahul verma said:
3 years ago
[BOD(in) - BOD(out)]/BOD(in)
[200-100]/200,
50.
[200-100]/200,
50.
(1)
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