Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 16 (Q.No. 30)
30.
What is the actual ground area covered by a 20 cm x 20 cm size vertical aerial photograph, at an average scale of 1 cm = 200 m having 60% forward overlap and 30% side overlap ?
Discussion:
3 comments Page 1 of 1.
NIRUPAMA PATRA said:
4 years ago
L= l(1-le)*s = 20(1-.6)*200= 1600m = 1.6 km
W=:20(1-.3)*200= 2800m= 2.8km
A = L * W = 1.6* 2.8= 4.48 km^.
W=:20(1-.3)*200= 2800m= 2.8km
A = L * W = 1.6* 2.8= 4.48 km^.
(1)
Chhaya said:
8 years ago
Thanks @Maruthi.
Maruthi said:
8 years ago
L=I(1-le)/s'.
L=I(1-le)/y200.
L= 1600m=1.6km.
Ground distance covered by photograph in transverse direction
W= w(1-ls)/s
W=20(1-0.3)/y200
= 2800m=2.8km.
Then area covered by one photograph.
A= LxW, = 1.6*2.8 = 4.48km2.
L=I(1-le)/y200.
L= 1600m=1.6km.
Ground distance covered by photograph in transverse direction
W= w(1-ls)/s
W=20(1-0.3)/y200
= 2800m=2.8km.
Then area covered by one photograph.
A= LxW, = 1.6*2.8 = 4.48km2.
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