Civil Engineering - UPSC Civil Service Exam Questions - Discussion

Discussion Forum : UPSC Civil Service Exam Questions - Section 10 (Q.No. 19)
19.
A bulldozer operates on a 30 m stretch and moves at 2.4 kmph when pushing the earth, and returns empty at 6 kmph. The time lost in loading and shifting gears per trip is 18 seconds. Its operating factor is nearly 50 min/hour. What is the number of trips made per hour ?
31
33
35
37
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Rahul verma said:   2 years ago
Thank you @Chhaya.
(1)

CHHAYA said:   7 years ago
2.4 km/h = 2.4*5/18 m/s = 0.66666 m/s.
6 km/h= 1.66666 m/s.

The time taking one trip = (30/0.666)+(30/1.6666)+18=45+18+18 = 81.
One trip time 81 second.
One hour trip 3600/81 = 44.4444,
But operation efficiency = 44.4444 * (50/60).
= 37.
(1)

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