Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 22 (Q.No. 41)
41.
What is the total degree of indeterminancy, both internal and external of the plane frame ?
Discussion:
3 comments Page 1 of 1.
Rahul said:
2 years ago
Ds = 3C-rr-sum(m-1).
= 3 * 4-0-(1+1),
= 10.
Dse= r - 3.
= 12 - 3.
= 9.
Dsi = 10-9
= 1.
= 3 * 4-0-(1+1),
= 10.
Dse= r - 3.
= 12 - 3.
= 9.
Dsi = 10-9
= 1.
Mahesh Bj said:
7 years ago
External Indeterminacy (Dse) = re-3 = 12-3 = 9 and,
Internal Indeterminacy (Dsi) = 3C-rr = (3*1)-2 = 1,
Total indeterminacy = Dse + Dsi = 9+1 = 10.
Internal Indeterminacy (Dsi) = 3C-rr = (3*1)-2 = 1,
Total indeterminacy = Dse + Dsi = 9+1 = 10.
Er. Saikat Saha said:
8 years ago
Degree of indeterminacy = (3m+r)-(3j+m'-1).
m= 10.
r= 4*3=12.
j= 10.
m'= no.of members connected to internal hinges = 3.
Degree of indeterminacy=(3m+r)-(3j+m'-1)=30+12-30-3+1=10.
m= 10.
r= 4*3=12.
j= 10.
m'= no.of members connected to internal hinges = 3.
Degree of indeterminacy=(3m+r)-(3j+m'-1)=30+12-30-3+1=10.
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