Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 10 (Q.No. 6)
6.
The figure shows a rigid frame fixed at A and hinged at C.
If a pure moment of 20 kNm is applied at B in the plane of the figure, then what is the moment at the fixed end A?
If a pure moment of 20 kNm is applied at B in the plane of the figure, then what is the moment at the fixed end A?
Discussion:
5 comments Page 1 of 1.
Rahul verma said:
3 years ago
DF= Kab/sum of K.
= 1/1+1.
= 1/2.
DM= 20*1/2,
= 10.
COM = DM/2 [FOR FIXED].
= 10/2,
= 5.
= 1/1+1.
= 1/2.
DM= 20*1/2,
= 10.
COM = DM/2 [FOR FIXED].
= 10/2,
= 5.
Noor said:
5 years ago
kab=1.
kbc=1.
d.f for BA = 1/2 = 0.5.
d.m for BA = 20 *m0.5=10,
c.o.m for AB = 10/2 = 5.
kbc=1.
d.f for BA = 1/2 = 0.5.
d.m for BA = 20 *m0.5=10,
c.o.m for AB = 10/2 = 5.
Jay said:
6 years ago
Far and fixed so carry over factor is 1/2 hence 20/2 so 10knm will be the answer.
Umesh said:
7 years ago
As per moment distribution method,
Make use of a concept called carry-over factor.
20 kn moment is carried to both the supports a and c equally.
20/4= 5.
Make use of a concept called carry-over factor.
20 kn moment is carried to both the supports a and c equally.
20/4= 5.
Srinu said:
9 years ago
Please give the explanation for the solution.
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