Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 19 (Q.No. 40)
40.
The deflection at the free end of a uniformly loaded cantilever of length 1 m is 7.5 mm. What is the slope at the free end ?
Discussion:
5 comments Page 1 of 1.
Swasan Toshin said:
6 years ago
(4/3) * (deflection/length) = (4/3) * (7.5/1000) = .01 radian.
Gautom Kr Mondal said:
5 years ago
The defection of a UDL cantilever beam= wl4/8EI and Slope =wl3/6EI.
So here we know deflection at free end =7.5 mm.7.5=wl4/8EI or w= 7.5x8xEI/l4, put this value in equation Slope, ie Slpoe= (7.5x8xEIxL3)/6xEIxL4=..01 radian.
So here we know deflection at free end =7.5 mm.7.5=wl4/8EI or w= 7.5x8xEI/l4, put this value in equation Slope, ie Slpoe= (7.5x8xEIxL3)/6xEIxL4=..01 radian.
Avi said:
5 years ago
We know,
Slope = θx.
7.5 = θ * 2/3 * L.
7.5 = θ * 2/3 * 1000.
θ = 0.01.
Slope = θx.
7.5 = θ * 2/3 * L.
7.5 = θ * 2/3 * 1000.
θ = 0.01.
Arnab kumar Barik said:
4 years ago
Given L = 1m = 1000 mm.
Deflection = 7.5 mm.
Slope = ?
We have Deflection = slope x 2/3L.
=> 7.5 = slope x 2/3 x 1000 = 0.01 radian.
Deflection = 7.5 mm.
Slope = ?
We have Deflection = slope x 2/3L.
=> 7.5 = slope x 2/3 x 1000 = 0.01 radian.
Chandan k s said:
4 years ago
Slope/deflection=(wl^3/6EI)/(wl^4/8EI),
(Slope/7.5) = (1÷6) /(8/L),
Slope/7.5 = (8/(6 * 1000));
Slope = 0.01 radian.
(Slope/7.5) = (1÷6) /(8/L),
Slope/7.5 = (8/(6 * 1000));
Slope = 0.01 radian.
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