Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 8 (Q.No. 5)
5.
A three-hinged circular arch ACB is formed by two quadrants of circles AC and BC of radii 2R and R respectively with C as crown, as shown in the figure at side. Consider the following in respect of the reactive forces developed at support A and B due to concentrated load W at the Crown.
1. Line of action RA at A is inclined as 45° to the horizontal.
2. VA = VB = W/2
3. HB = 2 HA
4. HA = HB = W/2
Which of the above is/are correct ?
1. Line of action RA at A is inclined as 45° to the horizontal.
2. VA = VB = W/2
3. HB = 2 HA
4. HA = HB = W/2
Which of the above is/are correct ?
Discussion:
4 comments Page 1 of 1.
Rahul verma said:
3 years ago
Va = Vb= W/2
by taking moment about crown get;
Vb = Hb = W/2
Va = Ha = W/2.
So, tanx = Va/Ha.
so the line of action is 45 degrees.
by taking moment about crown get;
Vb = Hb = W/2
Va = Ha = W/2.
So, tanx = Va/Ha.
so the line of action is 45 degrees.
(1)
Subha Annadurai said:
7 years ago
Please Explain the answer.
Ramadas said:
7 years ago
Please explain.
Abc said:
6 years ago
Yes, option C is the correct answer.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers