Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 26)
26.
A locomotive has four pairs of driving wheels carrying an axle load of 24 x 104 N. The maximum load that can be pulled if the coefficient of friction is 1/6, is
Discussion:
4 comments Page 1 of 1.
Farzan said:
3 years ago
But we should take the axle load on each driving wheel.
24/4 * 10^4 = 6 * 10^4.
24/4 * 10^4 = 6 * 10^4.
Deepak Dalal said:
8 years ago
Hauling Power = number of pairs of driving(n) wheel * weight on each driving axle(W) * coefficient of friction(f).
Here n= 4,
W = 24 * 10^4,
f = 1/6,
So hauling power = 4 * 24 * 10^4 * (1/6) =16 * 10^4.
Here n= 4,
W = 24 * 10^4,
f = 1/6,
So hauling power = 4 * 24 * 10^4 * (1/6) =16 * 10^4.
Vamshi said:
10 years ago
1 pair = (24x10^4) x (1\6).
= 4x10^4.
So we have 4 pairs multiple with 4.
Its 16x10^4.
= 4x10^4.
So we have 4 pairs multiple with 4.
Its 16x10^4.
Dunga ram siwasiya said:
1 decade ago
Hauling power of locomotive = Number of pairs of driving wheel x.
What on driving wheel x coefficient of friction?
What on driving wheel x coefficient of friction?
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