Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 32)
32.
For designing end bearing piles of square cross-section in clays having average unconfmed compressive strength of 6 t/m2, the net ultimate bearing capacity may be taken as
Discussion:
14 comments Page 2 of 2.
Yadvendra said:
6 years ago
Use Skempkons analysis for Nc.
take df/B =2.5 and b/l =1.
=> Nc=9.
Hence Q(be)=9*3,
= 27.
take df/B =2.5 and b/l =1.
=> Nc=9.
Hence Q(be)=9*3,
= 27.
(2)
Susnata said:
5 years ago
Answer is 27.
Apcivilian said:
4 years ago
Yes, the answer is 27.
(2)
Suraj Saqib said:
3 weeks ago
Here;
c = 6/2 = 3
Fos for piles = 6.
Net ultimate bearing capacity = 3 * 6.
= 18.
c = 6/2 = 3
Fos for piles = 6.
Net ultimate bearing capacity = 3 * 6.
= 18.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers