Civil Engineering - UPSC Civil Service Exam Questions - Discussion


For designing end bearing piles of square cross-section in clays having average unconfmed compressive strength of 6 t/m2, the net ultimate bearing capacity may be taken as

[A]. 15 t/m2
[B]. 18 t/m2
[C]. 20 t/m2
[D]. 27 t/m2

Answer: Option B


No answer description available for this question.

Gopinath said: (Oct 28, 2016)  
I think compressive strength = net sbc, so the factor of safety 3.

Zorox said: (Feb 17, 2017)  
According to terzaghi = 5.7*c .
Mayerhoff = 5.14c.
C = ucs/2.
C = 3.
For square footing;
Net bearing capacity = 1.3CNc.

Rahul said: (Apr 26, 2017)  
I think the answer should be 27 because it is asking about piles that too end bearing only so formula is 9C. Where c=3.

Maxp50 said: (Jun 9, 2017)  
According to me, the exact answer is 22.23. So the nearest option is C.

Sanjeev Kr Rai said: (Aug 2, 2017)  
Yes @Maxp50.

1.3cN = 1.3*6/2*5.72=22.3.

Dharshit said: (Oct 12, 2017)  
End bearing resistance;

Cu=Unconfined compression strength/Fos.
Cu=6/3 =2 t/m2.
Q=9*2 =18t/m2.

Darwin said: (Feb 6, 2018)  
For pile design the factor of safety must be 3. I think so.

Rahul said: (Apr 12, 2018)  
9cu and cu=qu/2 then Q=9x6/2=27.

Naresh Sreelam said: (Jun 13, 2018)  
Uc = 2c
C = 6/2 = 3.

In end bearing piles ultimate strength is 9c.

Anuj said: (Dec 9, 2019)  
In the pile foundation according to Meyerhof theory the value of end bearing capacity is 9c then Qup=9*3=27.

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