Civil Engineering - UPSC Civil Service Exam Questions - Discussion

32.

For designing end bearing piles of square cross-section in clays having average unconfmed compressive strength of 6 t/m2, the net ultimate bearing capacity may be taken as

 [A]. 15 t/m2 [B]. 18 t/m2 [C]. 20 t/m2 [D]. 27 t/m2

Explanation:

No answer description available for this question.

 Gopinath said: (Oct 28, 2016) I think compressive strength = net sbc, so the factor of safety 3.

 Zorox said: (Feb 17, 2017) According to terzaghi = 5.7*c . Mayerhoff = 5.14c. C = ucs/2. C = 3. For square footing; Net bearing capacity = 1.3CNc.

 Rahul said: (Apr 26, 2017) I think the answer should be 27 because it is asking about piles that too end bearing only so formula is 9C. Where c=3.

 Maxp50 said: (Jun 9, 2017) According to me, the exact answer is 22.23. So the nearest option is C.

 Sanjeev Kr Rai said: (Aug 2, 2017) Yes @Maxp50. 1.3cN = 1.3*6/2*5.72=22.3.

 Dharshit said: (Oct 12, 2017) End bearing resistance; Q=9Cu. Cu=Unconfined compression strength/Fos. Cu=6/3 =2 t/m2. Q=9*2 =18t/m2.

 Darwin said: (Feb 6, 2018) For pile design the factor of safety must be 3. I think so.

 Rahul said: (Apr 12, 2018) 9cu and cu=qu/2 then Q=9x6/2=27.

 Naresh Sreelam said: (Jun 13, 2018) Uc = 2c C = 6/2 = 3. In end bearing piles ultimate strength is 9c. 9*3=27.