Civil Engineering - UPSC Civil Service Exam Questions - Discussion

Discussion Forum : UPSC Civil Service Exam Questions - Section 15 (Q.No. 20)

UPSC Civil Service Exam Questions

20.

If the curve lead of a broad gauge railway turnout is 16.76 metres, the angle of crossing of the turnout will be given by

tan^-1 10

tan^-1 5

tan^-1 1/10

tan^-1 1/5

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

4 comments Page 1 of 1.

Manasha Pradhan said: 1 year ago

The right Answer is B.

Suman kumar said: 3 years ago

Option D is right curve lead =2GN= 2*1.67*N.

Apcivilian said: 3 years ago

I think option D is Right.

Abhishek said: 4 years ago

Answer should be D.

Curve lead = 2 * gauge * N.

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