Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 25)
25.
The shear force diagram of a beam is shown in the given figure. The absolute maximum bending moment in the beam is
Discussion:
6 comments Page 1 of 1.
Rahul verma said:
2 years ago
First draw the load diagram, and then calculate the bending moment from left or right support, you will get max BM at 12P loading of magnitude 5Pa.
Mushtaq Ahmad said:
3 years ago
B.M = Area of SFD.
Calculate the area of SFD and then by adding and subtracting you will come to know the Max B.M from the B.M.D.
Calculate the area of SFD and then by adding and subtracting you will come to know the Max B.M from the B.M.D.
Mohsin said:
7 years ago
The Maximum moment occurs where shear sign changes.
Max shear sign change is at distance "a" from left. Therefore moment at a = 5P x a.
Max shear sign change is at distance "a" from left. Therefore moment at a = 5P x a.
Immu said:
8 years ago
Position taken from ->
1st position =5unit downward
2nd position=12 unit upward
3rd posirion=9 unit downrd
4th position =4 unit upward
5th position = 2 unit downward
Now, calculate BM from LHS as u can see 5*a gives Max bm at 2nd position. You can also calculate from RHS side you will get the same result.
1st position =5unit downward
2nd position=12 unit upward
3rd posirion=9 unit downrd
4th position =4 unit upward
5th position = 2 unit downward
Now, calculate BM from LHS as u can see 5*a gives Max bm at 2nd position. You can also calculate from RHS side you will get the same result.
RAHUL said:
9 years ago
Explain it in detail. Please.
Sayandip basak said:
1 decade ago
Take moment from left,
+2p*a-2p*2a= -2pa.
Moving towards right,
-2pa+7p*a= 5pa.
Also at the extreme right we have 5p*a.
Therefore, maximum bending moment = 5p*a.
+2p*a-2p*2a= -2pa.
Moving towards right,
-2pa+7p*a= 5pa.
Also at the extreme right we have 5p*a.
Therefore, maximum bending moment = 5p*a.
(1)
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