# Civil Engineering - UPSC Civil Service Exam Questions - Discussion

18.

In a BG railway track, the specified ruling graident is 1 in 250. The horizontal curve of 3° on a gradient of 1 in 250 will have the permissible compensated gradient of

 [A]. 1 in 257 [B]. 1 in 357 [C]. 1 in 457 [D]. 1 in 512

Explanation:

No answer description available for this question.

 Hema Sumanth said: (Feb 10, 2018) Given ruling gradient = 1/250 * 100 = 0.4%. Grade compensation for B.G = 0.04 * 3 = 0.12. The permissible gradient = 0.4-0.12 = 0.28 that is 1/357.

 Arhaan Khan said: (Dec 13, 2020) @Hema Sumanth. How did you convert 0.28 into 1/357?

 Vishu said: (Jan 25, 2021) @Arhaan khan. 28/100 => 0.28.

 Nwibo Azubuike said: (Feb 22, 2021) How is 0.4% = 0.04? Explain.

 Johny Sins said: (Mar 18, 2021) @Nwibo Azubuike. 0.04 is the compensation value for B.G. It is not the value taken from the Ruling Gradient (0.4).

 Assumi said: (Jun 2, 2021) 0.28÷ 100 and 1÷357 gives the same value. Grade compensation value is in % so we are dividing 0.28 by 100.

 Saqib Sab said: (Aug 29, 2021) .04% * 3 = 0.12%, = (1/250)-(.12/100), = (100-30)/250*100, = 1/357.