Civil Engineering - UPSC Civil Service Exam Questions - Discussion

18. 

In a BG railway track, the specified ruling graident is 1 in 250. The horizontal curve of 3° on a gradient of 1 in 250 will have the permissible compensated gradient of

[A]. 1 in 257
[B]. 1 in 357
[C]. 1 in 457
[D]. 1 in 512

Answer: Option B

Explanation:

No answer description available for this question.

Hema Sumanth said: (Feb 10, 2018)  
Given ruling gradient = 1/250 * 100 = 0.4%.
Grade compensation for B.G = 0.04 * 3 = 0.12.
The permissible gradient = 0.4-0.12 = 0.28 that is 1/357.

Arhaan Khan said: (Dec 13, 2020)  
@Hema Sumanth.

How did you convert 0.28 into 1/357?

Vishu said: (Jan 25, 2021)  
@Arhaan khan.

28/100 => 0.28.

Nwibo Azubuike said: (Feb 22, 2021)  
How is 0.4% = 0.04? Explain.

Johny Sins said: (Mar 18, 2021)  
@Nwibo Azubuike.

0.04 is the compensation value for B.G.

It is not the value taken from the Ruling Gradient (0.4).

Assumi said: (Jun 2, 2021)  
0.28÷ 100 and 1÷357 gives the same value.

Grade compensation value is in % so we are dividing 0.28 by 100.

Saqib Sab said: (Aug 29, 2021)  
.04% * 3 = 0.12%,
= (1/250)-(.12/100),
= (100-30)/250*100,
= 1/357.

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