Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 21 (Q.No. 41)
41.
A shaft turns at 150 rpm under a torque of 1500 Nm. Power transmitted is
Discussion:
2 comments Page 1 of 1.
Viraj said:
10 years ago
Power = (2*pie*N*T)/60.
Sadashiva said:
7 years ago
Power=2πNT/60000 in K.
=2π * 150*1500/60000.
=7.5KW.
=2π * 150*1500/60000.
=7.5KW.
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