Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 19 (Q.No. 41)
41.
What will be the curve lead for a 1 in 8 1/2 turnout taking off from a straight broad gauge track?
Discussion:
2 comments Page 1 of 1.
Umesh JIT said:
7 years ago
Curve lead = 2 * Guage* N.
= 2 * 1.676 * 8.5.
= 2 * 1.676 * 8.5.
Munesh shukla said:
4 years ago
Curve lead = 2GN,
G = gauge = 1.676.
N = Number of crossing,
= 2 * 1.676 * 8.5 = 28.49.
G = gauge = 1.676.
N = Number of crossing,
= 2 * 1.676 * 8.5 = 28.49.
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