# Civil Engineering - UPSC Civil Service Exam Questions - Discussion

Discussion Forum : UPSC Civil Service Exam Questions - Section 11 (Q.No. 1)
1.
The initial and final void ratios of a clay sample in a consolidation test are 1 and 0.5, respectively. If the initial thickness of the sample is 2.4 cm, then its final thickness will be
1.3 cm
1.8 cm
1.9 cm
2.2 cm
Explanation:
No answer description is available. Let's discuss.
Discussion:
4 comments Page 1 of 1.

Saurabh Kumar said:   1 month ago
Change in settlement is =change in void ratio to 1 + initial void ratio × initial settlement.
So, 0.5×2.4÷2.
=0.6 so final settlement= 2.4 - 0.6 = 1.8.

Deepak Dalal said:   7 years ago
Total settlement (S) = change in void ratio/ (1+ intial void ratio) * thickness of layer.
So, S = 0.5 * 2.4/(1+1) = 0.6.

Then final thickness of layer = 2.4 - 0.6 = 1.8.

Deepak said:   7 years ago
According to me, the solution is;

dH/H = (e-e0)/(1+e0).
Hf = H-dH,
H = 2.4, e = 1.0 and e0 =0.50.

Barqat Sheikh said:   9 years ago
Final thickness = z (1+e2)/(1+e1).

= 2.4 (1+ 0.5)/(1+1) = 1.8.