Civil Engineering - UPSC Civil Service Exam Questions - Discussion

1. 

The initial and final void ratios of a clay sample in a consolidation test are 1 and 0.5, respectively. If the initial thickness of the sample is 2.4 cm, then its final thickness will be

[A]. 1.3 cm
[B]. 1.8 cm
[C]. 1.9 cm
[D]. 2.2 cm

Answer: Option B

Explanation:

No answer description available for this question.

Barqat Sheikh said: (Mar 14, 2015)  
Final thickness = z (1+e2)/(1+e1).

= 2.4 (1+ 0.5)/(1+1) = 1.8.

Deepak said: (Apr 10, 2017)  
According to me, the solution is;

dH/H = (e-e0)/(1+e0).
Hf = H-dH,
H = 2.4, e = 1.0 and e0 =0.50.

Deepak Dalal said: (May 1, 2017)  
Total settlement (S) = change in void ratio/ (1+ intial void ratio) * thickness of layer.
So, S = 0.5 * 2.4/(1+1) = 0.6.

Then final thickness of layer = 2.4 - 0.6 = 1.8.

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