Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 22 (Q.No. 39)
39.
When the bubble of a level tube was moved by 10 divisions, the change in staff intercept was 0.05 m. If the distance between the staff and the instrument was 100 m, then the senstitiveness of the bubble tube is given by
Discussion:
9 comments Page 1 of 1.
Dips said:
4 years ago
Sensitivity = (S/D N ) * 206265 = 10.3133.
S = 0.05,
D = 100,
N = 10.
Sensitivity =(0.05/100 * 0) * 206265 = 10.3 sec of arc.
S = 0.05,
D = 100,
N = 10.
Sensitivity =(0.05/100 * 0) * 206265 = 10.3 sec of arc.
(2)
Harish said:
7 years ago
Sensitivity = (S/D N ) * 206265 = 10.3133.
S = 0.05,
D = 100,
N = 10.
S = 0.05,
D = 100,
N = 10.
(1)
Sharad Bangar said:
5 years ago
1 rad = 206265 seconds.
(1)
Dolly said:
7 years ago
B is the correct option.
Ref: Gupta and Gupta.
Ref: Gupta and Gupta.
Blessi said:
6 years ago
Thank you @Harish.
Raju kumar said:
6 years ago
Thank you @Harish.
Asvin said:
6 years ago
Thanks @Harish.
Ankit said:
5 years ago
@Harish.
What is this random number 206265? explain it.
What is this random number 206265? explain it.
Hari said:
3 days ago
@Ankit.
π rad = 180°= 180 * 60 * 60 second,
So, 1 rad = 180 * 60 * 60/π second,
= 206264.80.
Approx 1 rad = 206265 second.
π rad = 180°= 180 * 60 * 60 second,
So, 1 rad = 180 * 60 * 60/π second,
= 206264.80.
Approx 1 rad = 206265 second.
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