Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 13)
13.
The absolute maximum Bending Moment in a simply supported beam of span 20 m due to moving udl of 4 t/m spanning over 5 m is
Discussion:
9 comments Page 1 of 1.
Nira said:
1 decade ago
How?
Divya said:
1 decade ago
How explain in detail?
Divya said:
1 decade ago
How? please explain with diagrammatically representation.
Michael Lalawmpuia said:
1 decade ago
Maximum Bending Moment will be at the simply supported beam mid span.
M at max = R1 (a+ (R1/2w)).
R1 = (wb (a+c+b) /2l).
Here, w = 4, a = 7.5, b = 5, c = 7.5, a+b+c = 20 = l.
Solving,
R1 = 10.
M max = 10 (7.5+ (10/2*5)) = 87.5 t-m.
Hope this clears up the doubts.
M at max = R1 (a+ (R1/2w)).
R1 = (wb (a+c+b) /2l).
Here, w = 4, a = 7.5, b = 5, c = 7.5, a+b+c = 20 = l.
Solving,
R1 = 10.
M max = 10 (7.5+ (10/2*5)) = 87.5 t-m.
Hope this clears up the doubts.
Gaurav said:
10 years ago
Max BM will be at mid span.
Taking moment about B we get.
R1 = (wb (a+b+c))/2l.
R1 = 10.
And calculating BM at center.
R1(a+b/2)-w(b/2) b/4).
10*(7.5+(5/2.5))- 4*(5/2)*(5/4) = 87.5 t-m.
Taking moment about B we get.
R1 = (wb (a+b+c))/2l.
R1 = 10.
And calculating BM at center.
R1(a+b/2)-w(b/2) b/4).
10*(7.5+(5/2.5))- 4*(5/2)*(5/4) = 87.5 t-m.
Shivendra said:
10 years ago
Max Bm will occur when load will be at mid span.
Now reaction will be same at both support i.e.
R1 = R2 = 4*5/2 = 10t.
Taking moment about midpoint of span, i.e.,
Absolute Max Bm = 10*10-4*2.5*1.25 = 87.5t-m.
Now reaction will be same at both support i.e.
R1 = R2 = 4*5/2 = 10t.
Taking moment about midpoint of span, i.e.,
Absolute Max Bm = 10*10-4*2.5*1.25 = 87.5t-m.
Saqib khattak said:
6 years ago
Thanks @Shivendra.
Satya said:
5 years ago
= load *span (where load working)/4(span -span (where load working)/2).
= w*x/4(s-x/2),
= 4*5/4(20-5/2),
= 87.5.
= w*x/4(s-x/2),
= 4*5/4(20-5/2),
= 87.5.
Manjunath Reddy said:
4 years ago
Ra+Rb = 4 * 5=20.
Ra=Rb = 10.
Max Bending Moment = Ra * 10 - 4 * 2.5 * 2.5/2
= 10 * 10-4 * 2.5 * 1.25
= 100-12.5.
= 87.5 at mid span.
Ra=Rb = 10.
Max Bending Moment = Ra * 10 - 4 * 2.5 * 2.5/2
= 10 * 10-4 * 2.5 * 1.25
= 100-12.5.
= 87.5 at mid span.
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