Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 4 (Q.No. 50)
50.
A beam of rectangular section 100 mm x 300 mm carries certain loads such that the Bending Moment at a section A is M ans at another section B it is (M + C).The distance between the sections A and B is 0.5 m and there are no external loads acting between the two sections. If the value of C is 10, 000 Nm, then the maximum shear stress is
Discussion:
3 comments Page 1 of 1.
VIJAY PAL said:
9 years ago
Shear force between A & B is;
Change in BM/Distance = 10000Nm/0.5 = 20000N.
Maximum shear stress =1.5V/bd =1.5 * 20000/0.1 * 0.3.
= 1.0MN/m2.
Change in BM/Distance = 10000Nm/0.5 = 20000N.
Maximum shear stress =1.5V/bd =1.5 * 20000/0.1 * 0.3.
= 1.0MN/m2.
(4)
Chhaya said:
8 years ago
Thanks @Vijay Pal.
(1)
Apcivilian said:
3 years ago
Nice, thanks for the explanation @Vijay Pal.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers