Civil Engineering - UPSC Civil Service Exam Questions - Discussion

4. 

A particle moves with simple harmonic motion. If its acceleration at distance 'D' from the equilibrium position is 'A' then the period of the motion is given by

[A]. AD
[B].
[C].
[D].

Answer: Option D

Explanation:

No answer description available for this question.

Bhupendra Sahu said: (Oct 13, 2015)  
Answer is D.

T = 2pi/w.

w = Angular velocity.

Now, A = -w^2*d.

w = [A/d]^1/2.

T = 2pi[d/A]^1/2.

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