Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 26 (Q.No. 49)
49.
A 600 mm long and 50 mm diameter rod of steel (E = 200 GPa, α = 12 x 10-6/°C) is attached at the ends to unyielding supports. When the temperature is 30°C there is no stress in the rod. After the temperature of the rod drops to - 20°C, the axial stress in the rod will be
Discussion:
2 comments Page 1 of 1.
Sai Krishna said:
5 years ago
Change in length = 600*12*10^-6*50 = 0.36mm,
Strain = 0.36/600 = 0.0006,
Stress = 0.0006*200*10^3 = 120MPa.
Strain = 0.36/600 = 0.0006,
Stress = 0.0006*200*10^3 = 120MPa.
Rahul said:
2 years ago
Thermal stress = ax(T2-T1)xE.
12x10^-6(-50)x200x10^9.
= -120Mpa
Attached at the ends to unyielding supports;
So, tensile stress.
12x10^-6(-50)x200x10^9.
= -120Mpa
Attached at the ends to unyielding supports;
So, tensile stress.
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