Civil Engineering - UPSC Civil Service Exam Questions - Discussion

10. 

Two particles of masses 21 gm and 28 gm are connected by a light inextensible string which passes over a fixed smooth pulley. The tension in the string in the ensuing motion will be

[A]. 7 gm. wt
[B]. 10 gm. wt
[C]. 12 gm. wt
[D]. 24 gm. wt

Answer: Option D

Explanation:

No answer description available for this question.

Chhaya said: (May 31, 2017)  
(2 * 21 * 28)/(21 + 28) = 24.

Jagwinder Singh Sidhu said: (Jan 21, 2021)  
Let's assume the tension T in the string.
Acceleration a in the string due to different loads,
Consider fbd of 21gm mass.
T-21g = 21a ----> (1)

Considering fbd of 28gm mass
28g - T = 28a ---> (2)
By solving these equations;
a = g/7.
T = 24g.

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