Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 21 (Q.No. 12)
12.
A 30 cm diameter friction pile is embedded 10 m into a homogeneous consolidated deposit. Unit adhesion developed between clay and pile shaft is 4 t/m2 and adhesion factor is 0.7. The safe load for factor of safety 2.5 will be
Discussion:
2 comments Page 1 of 1.
Phani said:
7 years ago
Ans = τ x π DL.
= α x C x π x D x L,
0.7x4x3.14x0.3x10 = 26.4,
Then, 26.4/2.5 = 10.55.
= α x C x π x D x L,
0.7x4x3.14x0.3x10 = 26.4,
Then, 26.4/2.5 = 10.55.
Rahul said:
3 years ago
Adhesion factor * cohesion * surface Area of pile.
a * C * A.
A = 2π * r * h.
.7*4*{2*3.14*.15*10}.
= 26.4.
safe load = 26.4/2.5.
= 10.55.
a * C * A.
A = 2π * r * h.
.7*4*{2*3.14*.15*10}.
= 26.4.
safe load = 26.4/2.5.
= 10.55.
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