Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 6 (Q.No. 37)
37.
A soil fails under an axial vertical stress of 100 kN/m2 in unconfined compression test. The failure plane makes an angle of 50° with the horizontal. The shear parameters c and φ respectively will be
Discussion:
11 comments Page 1 of 2.
Gabi said:
6 years ago
α= 45° + φ/2.
50=45 + φ/2.
φ/2 = 5, φ = 10.
50=45 + φ/2.
φ/2 = 5, φ = 10.
(1)
Riya said:
6 years ago
In UCS test,
σ1 = σ3 * tan^2 α + 2c tan a
But σ3 = 0
So the equation will be,
σ1 = 2c tan a.
Now, a =45° + π/2.
So, a = 45° + 10°/2.
a=50°.
Now,
σ1 = 100 kN /m^2.
100= 2c tan (50°).
So, c= 41.9 kN /m^2.
And π = 10°.
σ1 = σ3 * tan^2 α + 2c tan a
But σ3 = 0
So the equation will be,
σ1 = 2c tan a.
Now, a =45° + π/2.
So, a = 45° + 10°/2.
a=50°.
Now,
σ1 = 100 kN /m^2.
100= 2c tan (50°).
So, c= 41.9 kN /m^2.
And π = 10°.
(1)
Rahul verma said:
2 years ago
(&sigma)1 = (sigma)3 * tan^2(50) + 2Ctan50.
(&sigma)3=0 for the unconfined compression test.
(σ)1=2Ctan50.
C=100/2tan50,
C=41.9.
The failure plane angle = 45+x/2.
50=45+x/2
X=10
(&sigma)3=0 for the unconfined compression test.
(σ)1=2Ctan50.
C=100/2tan50,
C=41.9.
The failure plane angle = 45+x/2.
50=45+x/2
X=10
(1)
Apurbajyoti Neog said:
2 years ago
In the case of unconfined compression test Cohesion (C) = Qu/2=100/2 = 50 KN per square metre.
(1)
Amith S said:
7 years ago
The Answer should be B.
Sandy said:
7 years ago
I think the answer should be D.
Saurabh said:
6 years ago
σ 1 = σ 3 X (tan α) + 2c tan α.
Α = 50 °...σ 3 = 0 (because unconfined).
Hence σ1 = 2C tan α = 100.
Hence c = 41.9π = 10 °.
Α = 50 °...σ 3 = 0 (because unconfined).
Hence σ1 = 2C tan α = 100.
Hence c = 41.9π = 10 °.
Triza said:
6 years ago
How did you get the angle of resistance? @Saurabh.
Jadeja said:
6 years ago
How did you get an angle? Please explain.
Showkat said:
5 years ago
In an unconfined compression test c=sigma/2.
a=45+phi/2.
a=45+phi/2.
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