Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 2 (Q.No. 14)
14.
A mild steel flat subjected to a tensile force of 84 tonnes is connected to a gusset plate using rivets. If the forces required to shear a single rivet, to crush the rivet and to tear the plate per pitch length are 5000 kg, 8000 kg and 6000 kg respectively, then the number of rivets required is
Discussion:
2 comments Page 1 of 1.
Abhay said:
10 years ago
Strength of joints = Minimum of forces required to shear a single rivet, to crush the rivet and to tear the plate per pitch length.
= 5000 kg.
Number of rivets required to transmit pull of 84 tonnes = 84000/5000 = 16.8 say 17.
= 5000 kg.
Number of rivets required to transmit pull of 84 tonnes = 84000/5000 = 16.8 say 17.
(2)
Ravi said:
1 decade ago
Explain please.
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