Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 23 (Q.No. 17)
17.
A simply supported beam of span l and flexural rigidity EI, carries a unit point load at its centre. The strain energy in the beam due to bending is
Discussion:
8 comments Page 1 of 1.
Shashideep kumar said:
8 years ago
Please give the explanation of the solution.
Soumik said:
8 years ago
I think option A is correct.
Yc=wl^3/48 EI for simply supported beam with point load on its centre.
Yc=wl^3/48 EI for simply supported beam with point load on its centre.
Mohit singh said:
7 years ago
since strain energy due external load = 0.5 x W x deflection.
And deflection for that beam you know.
And deflection for that beam you know.
Yasir Ashrafi said:
7 years ago
The correct Answer must be A.
Jerish David said:
7 years ago
Correct answer is option C only.
U= Integral(M^2*ds/2EI).
M= Wl/4,
Where, W = 1(unit load),
Substitute and integrate,
You get, U = (W^2*l^3)/(96EI),
U = l^3/96EI.
U= Integral(M^2*ds/2EI).
M= Wl/4,
Where, W = 1(unit load),
Substitute and integrate,
You get, U = (W^2*l^3)/(96EI),
U = l^3/96EI.
Musthafa said:
7 years ago
u=.5 * w * deflection.
w=1, put deflection will get option C.
w=1, put deflection will get option C.
(1)
Kripa said:
6 years ago
U = 0.5*P*(PL^3)/96EI.
P = Load (unit load here).
U = L^3/96EI.
P = Load (unit load here).
U = L^3/96EI.
Deepinder Singh said:
5 years ago
The formula is = integral (M^2 dx/2EI).
M= WL/4 (as we know point load is given at the centre then the maximum bending moment is wl/4).
W= 1 (Unit load assume this value).
Substitute and Integrate using the formula:
You will get = (W^2 X L^3)/(96 EI).
Therefore the answer is = (L^3)/96EI.
M= WL/4 (as we know point load is given at the centre then the maximum bending moment is wl/4).
W= 1 (Unit load assume this value).
Substitute and Integrate using the formula:
You will get = (W^2 X L^3)/(96 EI).
Therefore the answer is = (L^3)/96EI.
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