Civil Engineering - UPSC Civil Service Exam Questions - Discussion

Discussion Forum : UPSC Civil Service Exam Questions - Section 8 (Q.No. 15)
15.
A rigid bar is supported by a spring as shown in the given figure.

The deflection of the point B will be
10 mm upward
20 mm downward
5 mm upward
40 mm downward.
Answer: Option
Explanation:

The Force in spring F = (500x2L)/L = 1000N.

Deflection in the spring δ = F/k = 1000/50 = 20mm.

Deflection at the point B = 2δ = 40mm downward.

Discussion:
2 comments Page 1 of 1.

Rahul verma said:   1 year ago
Here;
∑MA = 0,
R×L = 10×2L,
R = 2 kN.

Force in the spring=20 kN
F = Kx,
20kN = 1×x.
x = 20 mm.

Deflection under spring
= 20mm.

And by a similar triangle;
Deflection at B is 2x20 = 40mm.

Abhishek thakur said:   3 years ago
Stiffeners k= load per unit deflection.

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