Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 7 (Q.No. 28)
28.
A city supply of 15000 cubic metres of water per day is treated with a chlorine dosage of 0.5 ppm. For this purpose, the requirement of 25% bleaching powder per day would be
Discussion:
6 comments Page 1 of 1.
Niladri Nag said:
5 years ago
@Ubaithullah
BP required = cl2 dosge/ % Cl2 in BP.
0.5/25% = (0.5/25) * 100 = 2 mg/lit.
Total BP in kg = 15000 * 10 3 * 2 * 10^-6 = 30 kg.
And @Joysen.
It will be 10^-6. Because to convert mg to kg we need to multiply it with 10^-6.
BP required = cl2 dosge/ % Cl2 in BP.
0.5/25% = (0.5/25) * 100 = 2 mg/lit.
Total BP in kg = 15000 * 10 3 * 2 * 10^-6 = 30 kg.
And @Joysen.
It will be 10^-6. Because to convert mg to kg we need to multiply it with 10^-6.
(1)
Abhay kumar said:
6 years ago
0.5 x 15000 = 7500/1000 kg.
7.5 x 4 = 30 kg.
7.5 x 4 = 30 kg.
JoySen said:
7 years ago
@Ubaithullah.
Why you multiplied with 10^-6, it should be 10^-3 right?
Why you multiplied with 10^-6, it should be 10^-3 right?
Ubaithullah said:
7 years ago
BP required = cl2 dosge/ % Cl2 in BP.
0.5/25% = 0.2 mg /lit.
Total BP in kg = 15000 * 10 3 * 0.2 * 10^-6 = 30 kg.
0.5/25% = 0.2 mg /lit.
Total BP in kg = 15000 * 10 3 * 0.2 * 10^-6 = 30 kg.
(2)
Mahe said:
8 years ago
Please explain in detail @Harshada.
Harshada said:
9 years ago
0.5 x 15000 = 7500/1000 kg.
7.5 x 4 = 30 kg.
7.5 x 4 = 30 kg.
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