Civil Engineering - UPSC Civil Service Exam Questions - Discussion

1. 

A soil has a bulk density of 1.80 g/cm3 at water content of 5%. If the void ratio remains constant, then its bulk density for a water content of 10% will be

[A]. 1.88 g/cm3
[B]. 1.80 g/cm3
[C]. 1.98 g/cm3
[D]. 1.70 g/cm3

Answer: Option A

Explanation:

No answer description available for this question.

Pankaj Kalam said: (Apr 17, 2014)  
Bulk density Yb.
Dry Density Yd.
water content w.

Yb = Yd(1+w).
1.80 = Yd (1+.05).

Yd = 1.8/1.05.
Yd = 1.71.

Yb = 1.71*(1+.1).
Yb = 1.88.

Sinha said: (Oct 27, 2017)  
1.71*(1+.1).

Yb = 1.88. wrong.

Manu said: (Dec 30, 2017)  
1.88 is the right answer.

Sass said: (Feb 27, 2018)  
1.78 is the correct answer.

Pradeep Thogiti said: (Mar 10, 2018)  
For bulk density formula, further simplification we get;
(y2)/(y1) = (1+w2)/(1+w1),
=> y2/1.80 = (1+0.1)/(1+.05),
=>y2= 1.88.

Madhu said: (Nov 20, 2018)  
Please tell me how it is calculated?

Somenath Gorai said: (Nov 25, 2018)  
1.881gm/c^2.

Akshay Thakur said: (Dec 21, 2018)  
Option D is correct and the answer is 1.88 gm/cc.

Minnu Rajeev said: (Jan 5, 2020)  
Option D is the correct answer.

Rushikesh Patil said: (May 27, 2020)  
STEP 1. Y= 1.8/(1+0.05)
Y=1.71.

STEP 2. put y value in same formula,
1.71=x/(1+0.1),
X = 1.88.
(X is an unknown bulk density.)

Nithin S said: (Feb 3, 2021)  
Theoretically, adding water dosen't change dry density.

Hence, Yd is constant.

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