Civil Engineering - UPSC Civil Service Exam Questions - Discussion

4. 

A circular shaft subjected to torsion undergoes a twist of 1° in a length of 120 cm. If the maximum shear stress induced is limited to 1000 kg/cm2 and if modulus of rigidity G = 0.8 x 106 kg/cm2, then the radius of the shaft should be

[A]. π/18
[B]. 18/π
[C]. π/27
[D]. 27/π

Answer: Option D

Explanation:

No answer description available for this question.

Shyama Charan Shukla said: (Jun 29, 2016)  
Use formula t / r = T / J = G0/L.

0 angle in radian.

Parashuram Kagi said: (Nov 3, 2016)  
from The Torsion Equation we have,
T/J=GO/L=Fs/R here consider only GO/L= Fs/R,
From the data we have theta = 1, l = 120cm, toue = 1000kg/cm^2 and G = 0.8 X 10^6,
0.8 x 10^6 x 1/120 = 1000/R then Radius of shaft R = 27/3.142(Phi).

Pooja N V said: (Jul 11, 2020)  
r/R = G * angle &teeta;/L.
120/R = (0.8*10^5*1*π)/(1*10^3*180).
21.6 * 10^6 = 80*10^3*R*π.
R = 270/π.

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