Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 19 (Q.No. 8)
8.
A truss is shown in the given figure. The cross-sectional area of each member is 'A' and the modulus of elasticity of the material is E. The strain energy in the member XY is given by
Discussion:
2 comments Page 1 of 1.
PRATIK SEN said:
6 years ago
As we know,
Strain energy for any member (u) = p2l/2ae.
As here is no vertical force in the 'xy' member, so p=0.
So, u=0.
Strain energy for any member (u) = p2l/2ae.
As here is no vertical force in the 'xy' member, so p=0.
So, u=0.
Uttam said:
8 years ago
How? can anybody explain?
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