Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 19 (Q.No. 26)
26.
A simply supported beam of span 'L' and uniform flexural rigidly EI, carries a central load 'W' and total uniformly distributed load 'W' throughout the span. The maximum deflection is given by
Discussion:
5 comments Page 1 of 1.
Shahid said:
1 year ago
How option D is correct?
The deflection in SSB with UDL is 5wl⁴/384EI.
The deflection in SSB with UDL is 5wl⁴/384EI.
(1)
Dipankar Gupta said:
4 years ago
Max. Deflection due to a concentrated load at the centre
=WL^3/48EI.
Max. Deflection due to total uniformly distributed load W =5WL^3/384EI.
Total MAX. DEFLECTION= WL^3/48EI+WL^3/384EI=13WL^3/384EI.
=WL^3/48EI.
Max. Deflection due to total uniformly distributed load W =5WL^3/384EI.
Total MAX. DEFLECTION= WL^3/48EI+WL^3/384EI=13WL^3/384EI.
(3)
Ridham said:
4 years ago
How option D?
Deflection in SSB carrying UDL is 5wl^4/384EI.
Deflection in SSB carrying UDL is 5wl^4/384EI.
Bhutan said:
6 years ago
D is correct. I agree with the given answer.
(1)
Harish said:
7 years ago
I think Option B is Correct.
(1)
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