Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 16)
16.
In the force system shown in the figure, the force CA should be
Discussion:
7 comments Page 1 of 1.
SHIVA KUMAR M N said:
4 years ago
R= √(F1^2+F2^2+2F1 F2 cos (θ) is general formula.
Here theta is 90 °ree;. cos90=0.
Hence R= √(3^2+4^2)=5t.
Here theta is 90 °ree;. cos90=0.
Hence R= √(3^2+4^2)=5t.
(1)
Saurabh Kadam said:
5 years ago
Is there fixed formula for resultant force?
Zinabe molla said:
8 years ago
Resultant force = ((horizontal force)^2 + (vertical force)^2))^1/2.
= ((4t^2) + (3t^2))^1/2.
= 5t.
= ((4t^2) + (3t^2))^1/2.
= 5t.
Asaithambi said:
9 years ago
Resultant force = ((horizontal force)^2 + (vertical force)^2))^1/2.
= ((4t^2) + (3t^2))^1/2.
= 5t.
= ((4t^2) + (3t^2))^1/2.
= 5t.
Logu said:
1 decade ago
This formula is used for center line marking.
ARBINA said:
1 decade ago
3^2+4^2 = SQUARE OF ANSWER.
25 = SQUARE OF ANSWER.
TAKING SQUARE ROOT ON BOTH SIDE SO,
5 = ANSWER.
25 = SQUARE OF ANSWER.
TAKING SQUARE ROOT ON BOTH SIDE SO,
5 = ANSWER.
Chnadu said:
1 decade ago
3^2+4^2 = 25.
%25 = 5.
And the direction same as shown.
%25 = 5.
And the direction same as shown.
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