Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 27 (Q.No. 28)
28.
A steel cable of 2 cm diameter is used to lift a load of 500π kg. Given that, E = 2 x 106 kg/cm2 and the length of the cable is 10 m, the elongation of the cable due to the load will be
Discussion:
7 comments Page 1 of 1.
Vimal sharma said:
4 years ago
Here, Elongation = p*I/a*e.
Rishi bhatt said:
5 years ago
Because elongation due to load, not by self-weight.
So, PL/AE.
So, PL/AE.
Arjun said:
5 years ago
Yes, P*l/ AE is right.
Smita said:
5 years ago
PL÷AE
where P=500 π; kg , L=10*100cm, A=π*(2÷2)^2 cm^2, E=2*10^6 kg/cm^2.
where P=500 π; kg , L=10*100cm, A=π*(2÷2)^2 cm^2, E=2*10^6 kg/cm^2.
(1)
Abhilash said:
7 years ago
According to me, it is 0.5 cm.
Please explain the answer in detail.
Please explain the answer in detail.
Asaithambi said:
9 years ago
Elongation = (p*l)/(A*E).
Savitri said:
9 years ago
Give the explanation for this question.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers