Civil Engineering - UPSC Civil Service Exam Questions - Discussion

3. 

A saturated stiff clay has unit weight 2 gm/cm3 and unconfined compressive strength 2 kg/cm2. The depth of tension crack that would develop in this clay is

[A]. 2 m
[B]. 5 m
[C]. 10 m
[D]. 20 m

Answer: Option A

Explanation:

No answer description available for this question.

Deepak said: (Nov 25, 2015)  
Depth of tension crack, d = (2xC)/Y = 2.0 m.

C = Unconfined compressive strength.

Y = Saturated unit weight.

And, maximum unsupported depth of cutting = 2d.

Chhaya said: (Jun 27, 2017)  
Thanks @Deepak.

Karthika.C said: (Jul 23, 2017)  
The answer should be 20m. Not 2m as per unit conversion. Please explain it.

Abhijeet said: (Jul 26, 2017)  
Depth of tension crack= 2c/Y.
Where c= cohesion.
And from unconfined compression shear test cohesion = q/2 , q=unconfined compressive strenght.
So answer is 10 m.
@Deepak C = cohesion.=q/2.

Mrinmoy Nath said: (Sep 4, 2017)  
Yes, correct @Abhijeet.

Chandru said: (Feb 1, 2018)  
Yes, the answer is 10m.

Umesh Jit said: (Sep 18, 2018)  
C= q/2 = 1.

D = 2 c/ GAMMA.
= 2*1/ 0.002.
= 1000 cm.
= 10 m.

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