# Civil Engineering - UPSC Civil Service Exam Questions - Discussion

3.

A saturated stiff clay has unit weight 2 gm/cm3 and unconfined compressive strength 2 kg/cm2. The depth of tension crack that would develop in this clay is

 [A]. 2 m [B]. 5 m [C]. 10 m [D]. 20 m

Explanation:

No answer description available for this question.

 Deepak said: (Nov 25, 2015) Depth of tension crack, d = (2xC)/Y = 2.0 m. C = Unconfined compressive strength. Y = Saturated unit weight. And, maximum unsupported depth of cutting = 2d.

 Chhaya said: (Jun 27, 2017) Thanks @Deepak.

 Karthika.C said: (Jul 23, 2017) The answer should be 20m. Not 2m as per unit conversion. Please explain it.

 Abhijeet said: (Jul 26, 2017) Depth of tension crack= 2c/Y. Where c= cohesion. And from unconfined compression shear test cohesion = q/2 , q=unconfined compressive strenght. So answer is 10 m. @Deepak C = cohesion.=q/2.

 Mrinmoy Nath said: (Sep 4, 2017) Yes, correct @Abhijeet.

 Chandru said: (Feb 1, 2018) Yes, the answer is 10m.

 Umesh Jit said: (Sep 18, 2018) C= q/2 = 1. D = 2 c/ GAMMA. = 2*1/ 0.002. = 1000 cm. = 10 m.