Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 20 (Q.No. 24)
24.
A vane 20 cm long and 10 cm in diameter was pressed into a soft marine clay at the bottom of a bore hole. Torque was applied gradually and failure occurred at 1000 kg cm. The cohesion of the clay in kg/cm2 is :
Discussion:
5 comments Page 1 of 1.
Ronak Bamania said:
2 years ago
S = T/π [ (D²H)/2 + (D³/6)].
S = 1000/π [ (10²x20)/2 + (10³)/6].
S = (1/π)x(6/7).
Option A is Right.
S = 1000/π [ (10²x20)/2 + (10³)/6].
S = (1/π)x(6/7).
Option A is Right.
Raju kumar said:
4 years ago
Right, thanks @Priyanka.
Priyanka said:
5 years ago
A is correct.
S = T/piD*2(H/2+D/6).
S = 6/7pi.
S = T/piD*2(H/2+D/6).
S = 6/7pi.
Chauhan said:
5 years ago
How to solve this? Explain anyone.
Umesh JIT said:
7 years ago
The Answer should be A.
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