Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 9 (Q.No. 18)
18.
The ratio of pressures between two points A and B located respectively at depths 0.5 m, and 2 m below a constant level of water in a tank is
Discussion:
2 comments Page 1 of 1.
Amrit raj negi said:
9 years ago
Pressure= p(roh) * g * h,
For depth of 0.5m.
= 1 * 9.81 * 0.5,
= 4.905,
For depth of 2m
= 1 * 9.81 * 2,
= 19.62.
Therefore ratio = 4.905/19.62 = 0.25 = 1/4.
For depth of 0.5m.
= 1 * 9.81 * 0.5,
= 4.905,
For depth of 2m
= 1 * 9.81 * 2,
= 19.62.
Therefore ratio = 4.905/19.62 = 0.25 = 1/4.
(1)
Pops said:
9 years ago
0.5/2 = 1/4 => 1 : 4.
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