Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 27 (Q.No. 17)
17.
A simply supported beam of uniform cross-section is subjected to a maximum bending moment of 2.25 t.m. If it has rectangular cross-section with width 15 cm and depth 30 cm, then the maximum bending stress induced in the beam will be
Discussion:
2 comments Page 1 of 1.
Swar said:
6 years ago
Thanks @Michael.
(1)
MICHAEL LALAWMPUIA said:
8 years ago
We have the realtion,
σ = My / I ...........(1).
Where, Max Bending Stress = (Max Bending Moment * neutral axis) / Moment of Inertia,
Here, Max Bending Moment = 2.25 tm = 225000 kg cm,
Neutral Axis = 30/2 = 15 cm,
Moment of Inertia = (bh^3)/12= (15*30^3)/12= 33750 cm4.
Putting values in (1),
Maximum Bending Stress = 100 kg/cm2.
σ = My / I ...........(1).
Where, Max Bending Stress = (Max Bending Moment * neutral axis) / Moment of Inertia,
Here, Max Bending Moment = 2.25 tm = 225000 kg cm,
Neutral Axis = 30/2 = 15 cm,
Moment of Inertia = (bh^3)/12= (15*30^3)/12= 33750 cm4.
Putting values in (1),
Maximum Bending Stress = 100 kg/cm2.
(3)
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