Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 24 (Q.No. 30)
30.
A motor shaft rotating with a speed of 90 rpm decelerates uniformly when the motor is switched off and stops in 40 sec. The number of revolutions made by the shaft in this time would be
Discussion:
2 comments Page 1 of 1.
Harish said:
7 years ago
(0 + 90) /2 = 45 rpm.
N = 45 * 40 sec/60 sec,
= 30.
N = 45 * 40 sec/60 sec,
= 30.
(1)
Pradeep said:
7 years ago
Please explain it.
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