Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 10 (Q.No. 40)
40.
The radius of curvature of an ideal transition curve should be
Discussion:
8 comments Page 1 of 1.
Amit said:
6 years ago
e= BV^2/gR. So 1/R is radius of curvature is directly proportional to superelevation. So correct answer is D.
Basu said:
7 years ago
I think option A is the correct answer.
RAJINDER SAINI said:
8 years ago
According to me, the correct answer A.
Priyanka said:
5 years ago
e +f = V^2/r
A is correct
L=v^2/r
A is correct
L=v^2/r
Amithsid said:
7 years ago
Answer A is only correct option.
Swarup sen chowdhury said:
7 years ago
No, D is the correct answer.
Mastram meena said:
5 years ago
The Correct answer is A.
Pramod said:
8 years ago
Yes, I agree @Rajinder
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