Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 10 (Q.No. 3)
3.
Based on the Gaussian law of distribution of random errors, the number of errors that are expected to exceed the limit of ± a, where 0 represents the standard deviation, out of 1000 observations is
Discussion:
3 comments Page 1 of 1.
Rishabh said:
8 months ago
+/- 1a contain 68.3% area or (error).
So remain - (100-68.3) = 31.7.
Then the Number of error = (31.7/100) * 1000 = 317.
So remain - (100-68.3) = 31.7.
Then the Number of error = (31.7/100) * 1000 = 317.
Erick said:
7 years ago
Based on Gaussian law.
68.3% no. of errors at limit +/- 1a.
95.4% w/in +/- 2a.
99.7% w/in +/- 3a.
Therefore; no.of errors = 1000-(1000 * 68.3/100) = 317.
68.3% no. of errors at limit +/- 1a.
95.4% w/in +/- 2a.
99.7% w/in +/- 3a.
Therefore; no.of errors = 1000-(1000 * 68.3/100) = 317.
Subha Annadurai said:
7 years ago
Anyone explain it.
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